Algorithms_in_C 1.0.0
Set of algorithms implemented in C.
ode_semi_implicit_euler.c File Reference

Solve a multivariable first order ordinary differential equation (ODEs) using semi implicit Euler method More...

#include <math.h>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
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Macros

#define order   2
 number of dependent variables in problem
 

Functions

void problem (const double *x, double *y, double *dy)
 Problem statement for a system with first-order differential equations. More...
 
void exact_solution (const double *x, double *y)
 Exact solution of the problem. More...
 
void semi_implicit_euler_step (double dx, double *x, double *y, double *dy)
 Compute next step approximation using the semi-implicit-Euler method. More...
 
double semi_implicit_euler (double dx, double x0, double x_max, double *y, char save_to_file)
 Compute approximation using the semi-implicit-Euler method in the given limits. More...
 
int main (int argc, char *argv[])
 Main Function. More...
 

Detailed Description

Solve a multivariable first order ordinary differential equation (ODEs) using semi implicit Euler method

Authors
Krishna Vedala

The ODE being solved is:

\begin{eqnarray*} \dot{u} &=& v\\ \dot{v} &=& -\omega^2 u\\ \omega &=& 1\\ [x_0, u_0, v_0] &=& [0,1,0]\qquad\ldots\text{(initial values)} \end{eqnarray*}

The exact solution for the above problem is:

\begin{eqnarray*} u(x) &=& \cos(x)\\ v(x) &=& -\sin(x)\\ \end{eqnarray*}

The computation results are stored to a text file semi_implicit_euler.csv and the exact soltuion results in exact.csv for comparison. Implementation solution

To implement Van der Pol oscillator, change the problem function to:

const double mu = 2.0;
dy[0] = y[1];
dy[1] = mu * (1.f - y[0] * y[0]) * y[1] - y[0];

Van der Pol Oscillator solution

See also
ode_forward_euler.c, ode_midpoint_euler.c

Function Documentation

◆ exact_solution()

void exact_solution ( const double *  x,
double *  y 
)

Exact solution of the problem.

Used for solution comparison.

Parameters
[in]xindependent variable
[in,out]ydependent variable
72{
73 y[0] = cos(x[0]);
74 y[1] = -sin(x[0]);
75}

◆ main()

int main ( int  argc,
char *  argv[] 
)

Main Function.

148{
149 double X0 = 0.f; /* initial value of x0 */
150 double X_MAX = 10.F; /* upper limit of integration */
151 double Y0[] = {1.f, 0.f}; /* initial value Y = y(x = x_0) */
152 double step_size;
153
154 if (argc == 1)
155 {
156 printf("\nEnter the step size: ");
157 scanf("%lg", &step_size);
158 }
159 else
160 // use commandline argument as independent variable step size
161 step_size = atof(argv[1]);
162
163 // get approximate solution
164 double total_time = semi_implicit_euler(step_size, X0, X_MAX, Y0, 1);
165 printf("\tTime = %.6g ms\n", total_time);
166
167 /* compute exact solution for comparion */
168 FILE *fp = fopen("exact.csv", "w+");
169 if (fp == NULL)
170 {
171 perror("Error! ");
172 return -1;
173 }
174 double x = X0;
175 double *y = &(Y0[0]);
176 printf("Finding exact solution\n");
177 clock_t t1 = clock();
178
179 do
180 {
181 fprintf(fp, "%.4g,%.4g,%.4g\n", x, y[0], y[1]); // write to file
182 exact_solution(&x, y);
183 x += step_size;
184 } while (x <= X_MAX);
185
186 clock_t t2 = clock();
187 total_time = (t2 - t1) / CLOCKS_PER_SEC;
188 printf("\tTime = %.6g ms\n", total_time);
189 fclose(fp);
190
191 return 0;
192}
void exact_solution(const double *x, double *y)
Exact solution of the problem.
Definition: ode_semi_implicit_euler.c:71
double semi_implicit_euler(double dx, double x0, double x_max, double *y, char save_to_file)
Compute approximation using the semi-implicit-Euler method in the given limits.
Definition: ode_semi_implicit_euler.c:109
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◆ problem()

void problem ( const double *  x,
double *  y,
double *  dy 
)

Problem statement for a system with first-order differential equations.

Updates the system differential variables.

Note
This function can be updated to and ode of any order.
Parameters
[in]xindependent variable(s)
[in,out]ydependent variable(s)
[in,out]dyfirst-derivative of dependent variable(s)
59{
60 const double omega = 1.F; // some const for the problem
61 dy[0] = y[1]; // x dot
62 dy[1] = -omega * omega * y[0]; // y dot
63}

◆ semi_implicit_euler()

double semi_implicit_euler ( double  dx,
double  x0,
double  x_max,
double *  y,
char  save_to_file 
)

Compute approximation using the semi-implicit-Euler method in the given limits.

Parameters
[in]dxstep size
[in]x0initial value of independent variable
[in]x_maxfinal value of independent variable
[in,out]ytake \(y_n\) and compute \(y_{n+1}\)
[in]save_to_fileflag to save results to a CSV file (1) or not (0)
Returns
time taken for computation in seconds
111{
112 double dy[order];
113
114 FILE *fp = NULL;
115 if (save_to_file)
116 {
117 fp = fopen("semi_implicit_euler.csv", "w+");
118 if (fp == NULL)
119 {
120 perror("Error! ");
121 return -1;
122 }
123 }
124
125 /* start integration */
126 clock_t t1 = clock();
127 double x = x0;
128 do // iterate for each step of independent variable
129 {
130 if (save_to_file && fp)
131 fprintf(fp, "%.4g,%.4g,%.4g\n", x, y[0], y[1]); // write to file
132 semi_implicit_euler_step(dx, &x, y, dy); // perform integration
133 x += dx; // update step
134 } while (x <= x_max); // till upper limit of independent variable
135 /* end of integration */
136 clock_t t2 = clock();
137
138 if (save_to_file && fp)
139 fclose(fp);
140
141 return (double)(t2 - t1) / CLOCKS_PER_SEC;
142}
void semi_implicit_euler_step(double dx, double *x, double *y, double *dy)
Compute next step approximation using the semi-implicit-Euler method.
Definition: ode_semi_implicit_euler.c:85
#define order
number of dependent variables in problem
Definition: ode_semi_implicit_euler.c:47
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◆ semi_implicit_euler_step()

void semi_implicit_euler_step ( double  dx,
double *  x,
double *  y,
double *  dy 
)

Compute next step approximation using the semi-implicit-Euler method.

Parameters
[in]dxstep size
[in,out]xtake \(x_n\) and compute \(x_{n+1}\)
[in,out]ytake \(y_n\) and compute \(y_{n+1}\)
[in,out]dycompute \(y_n+\frac{1}{2}dx\,f\left(x_n,y_n\right)\)
86{
87 int o;
88
89 problem(x, y, dy); // update dy once
90 y[0] += dx * dy[0]; // update y0
91
92 problem(x, y, dy); // update dy once more
93
94 for (o = 1; o < order; o++)
95 y[o] += dx * dy[o]; // update remaining using new dy
96 *x += dx;
97}
void problem(const double *x, double *y, double *dy)
Problem statement for a system with first-order differential equations.
Definition: ode_semi_implicit_euler.c:58
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