tests: add sub-surface tree destruction permutations
Add a test for varying the object destruction order in a complex sub-surface tree. This test attemps to fuzz the destruction of a sub-surface tree to make sure the server does not crash on any wl_surface or wl_subsurface destruction sequence. Signed-off-by: Pekka Paalanen <pekka.paalanen@collabora.co.uk>
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@ -24,6 +24,7 @@
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#include "weston-test-client-helper.h"
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#include "subsurface-client-protocol.h"
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#include <stdio.h>
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#define NUM_SUBSURFACES 3
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@ -323,3 +324,204 @@ TEST(test_subsurface_destroy_protocol)
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client_roundtrip(client);
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}
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static void
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create_subsurface_tree(struct client *client, struct wl_surface **surfs,
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struct wl_subsurface **subs, int n)
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{
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struct wl_subcompositor *subco;
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int i;
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subco = get_subcompositor(client);
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for (i = 0; i < n; i++)
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surfs[i] = wl_compositor_create_surface(client->wl_compositor);
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/*
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* The tree of sub-surfaces:
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* 0
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* / \
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* 1 2 - 10
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* / \ |\
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* 3 5 9 6
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* / / \
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* 4 7 8
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* Surface 0 has no wl_subsurface, others do.
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*/
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switch (n) {
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default:
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assert(0);
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break;
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#define SUB_LINK(s,p) \
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subs[s] = wl_subcompositor_get_subsurface(subco, surfs[s], surfs[p])
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case 11:
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SUB_LINK(10, 2);
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case 10:
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SUB_LINK(9, 2);
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case 9:
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SUB_LINK(8, 6);
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case 8:
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SUB_LINK(7, 6);
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case 7:
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SUB_LINK(6, 2);
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case 6:
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SUB_LINK(5, 1);
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case 5:
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SUB_LINK(4, 3);
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case 4:
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SUB_LINK(3, 1);
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case 3:
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SUB_LINK(2, 0);
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case 2:
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SUB_LINK(1, 0);
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#undef SUB_LINK
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};
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}
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static void
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destroy_subsurface_tree(struct wl_surface **surfs,
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struct wl_subsurface **subs, int n)
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{
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int i;
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for (i = n; i-- > 0; ) {
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if (surfs[i])
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wl_surface_destroy(surfs[i]);
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if (subs[i])
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wl_subsurface_destroy(subs[i]);
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}
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}
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static int
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has_dupe(int *cnt, int n)
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{
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int i;
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for (i = 0; i < n; i++)
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if (cnt[i] == cnt[n])
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return 1;
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return 0;
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}
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/* Note: number of permutations to test is: set_size! / (set_size - NSTEPS)!
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*/
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#define NSTEPS 3
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struct permu_state {
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int set_size;
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int cnt[NSTEPS];
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};
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static void
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permu_init(struct permu_state *s, int set_size)
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{
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int i;
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s->set_size = set_size;
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for (i = 0; i < NSTEPS; i++)
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s->cnt[i] = 0;
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}
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static int
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permu_next(struct permu_state *s)
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{
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int k;
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s->cnt[NSTEPS - 1]++;
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while (1) {
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if (s->cnt[0] >= s->set_size) {
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return -1;
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}
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for (k = 1; k < NSTEPS; k++) {
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if (s->cnt[k] >= s->set_size) {
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s->cnt[k - 1]++;
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s->cnt[k] = 0;
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break;
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}
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if (has_dupe(s->cnt, k)) {
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s->cnt[k]++;
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break;
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}
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}
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if (k == NSTEPS)
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return 0;
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}
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}
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static void
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destroy_permu_object(struct wl_surface **surfs,
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struct wl_subsurface **subs, int i)
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{
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int h = (i + 1) / 2;
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if (i & 1) {
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fprintf(stderr, " [sub %2d]", h);
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wl_subsurface_destroy(subs[h]);
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subs[h] = NULL;
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} else {
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fprintf(stderr, " [surf %2d]", h);
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wl_surface_destroy(surfs[h]);
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surfs[h] = NULL;
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}
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}
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TEST(test_subsurface_destroy_permutations)
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{
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/*
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* Test wl_surface and wl_subsurface destruction orders in a
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* complex tree of sub-surfaces.
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*
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* In the tree of sub-surfaces, go through every possible
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* permutation of destroying all wl_surface and wl_subsurface
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* objects. Execpt, to limit running time to a reasonable level,
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* execute only the first NSTEPS destructions from each
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* permutation, and ignore identical cases.
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*/
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const int test_size = 11;
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struct client *client;
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struct wl_surface *surfs[test_size];
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struct wl_subsurface *subs[test_size];
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struct permu_state per;
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int counter = 0;
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int i;
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client = client_create(100, 50, 123, 77);
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assert(client);
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permu_init(&per, test_size * 2 - 1);
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while (permu_next(&per) != -1) {
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/* for each permutation of NSTEPS out of test_size */
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memset(surfs, 0, sizeof surfs);
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memset(subs, 0, sizeof subs);
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create_subsurface_tree(client, surfs, subs, test_size);
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fprintf(stderr, "permu");
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for (i = 0; i < NSTEPS; i++)
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fprintf(stderr, " %2d", per.cnt[i]);
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for (i = 0; i < NSTEPS; i++)
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destroy_permu_object(surfs, subs, per.cnt[i]);
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fprintf(stderr, "\n");
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client_roundtrip(client);
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destroy_subsurface_tree(surfs, subs, test_size);
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counter++;
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}
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client_roundtrip(client);
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fprintf(stderr, "tried %d destroy permutations\n", counter);
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}
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