tinycc/tests/tests2/94_generic.c
Petr Skocik 314843ffc3 Fix how _Generic treats pointers to arrays.
_Generic should distinguish pointers to differently sized
arrays such as `int(*)[2]` and `int(*)[4]`.
2018-11-12 20:52:14 +01:00

76 lines
1.5 KiB
C

#include <stdio.h>
const int a = 0;
struct a {
int a;
};
struct b {
int a;
};
int a_f()
{
return 20;
}
int b_f()
{
return 10;
}
typedef int (*fptr)(int);
int foo(int i)
{
return i;
}
typedef int int_type1;
#define gen_sw(a) _Generic(a, const char *: 1, default: 8, int: 123);
int main()
{
int i = 0;
signed long int l = 2;
struct b titi;
const int * const ptr;
const char *ti;
int_type1 i2;
i = _Generic(a, int: a_f, const int: b_f)();
printf("%d\n", i);
i = _Generic(a, int: a_f() / 2, const int: b_f() / 2);
printf("%d\n", i);
i = _Generic(ptr, int *:1, int * const:2, default:20);
printf("%d\n", i);
i = gen_sw(a);
printf("%d\n", i);
i = _Generic(titi, struct a:1, struct b:2, default:20);
printf("%d\n", i);
i = _Generic(i2, char: 1, int : 0);
printf("%d\n", i);
i = _Generic(a, char:1, int[4]:2, default:5);
printf("%d\n", i);
i = _Generic(17, int :1, int **:2);
printf("%d\n", i);
i = _Generic(17L, int :1, long :2, long long : 3);
printf("%d\n", i);
i = _Generic("17, io", char *: 3, const char *: 1);
printf("%d\n", i);
i = _Generic(ti, const unsigned char *:1, const char *:4, char *:3,
const signed char *:2);
printf("%d\n", i);
printf("%s\n", _Generic(i + 2L, long: "long", int: "int",
long long: "long long"));
i = _Generic(l, long: 1, int: 2);
printf("%d\n", i);
i = _Generic(foo, fptr: 3, int: 4);
printf("%d\n", i);
(void)_Generic((int(*)[2]){0}, int(*)[2]:0, int(*)[4]:0); //shouldn't match twice
return 0;
}