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Fix function to pointer conversion

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This snippet is valid:
  void foo(void);
  ... foo + 42 ...
the function designator is converted to pointer to function
implicitely.  gen_op didn't do that and bailed out.
This commit is contained in:
Michael Matz 2016-07-14 04:09:49 +02:00
parent e034853b38
commit 662338f116
2 changed files with 20 additions and 0 deletions
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13
tccgen.c
View File

@ -1926,6 +1926,7 @@ ST_FUNC void gen_op(int op)
int u, t1, t2, bt1, bt2, t;
CType type1;
redo:
t1 = vtop[-1].type.t;
t2 = vtop[0].type.t;
bt1 = t1 & VT_BTYPE;
@ -1933,6 +1934,18 @@ ST_FUNC void gen_op(int op)
if (bt1 == VT_STRUCT || bt2 == VT_STRUCT) {
tcc_error("operation on a struct");
} else if (bt1 == VT_FUNC || bt2 == VT_FUNC) {
if (bt2 == VT_FUNC) {
mk_pointer(&vtop->type);
gaddrof();
}
if (bt1 == VT_FUNC) {
vswap();
mk_pointer(&vtop->type);
gaddrof();
vswap();
}
goto redo;
} else if (bt1 == VT_PTR || bt2 == VT_PTR) {
/* at least one operand is a pointer */
/* relationnal op: must be both pointers */

7
tests/tcctest.c
View File

@ -1847,6 +1847,7 @@ void funcptr_test()
int dummy;
void (*func)(int);
} st1;
long diff;
printf("funcptr:\n");
func = #
@ -1862,6 +1863,12 @@ void funcptr_test()
printf("sizeof2 = %d\n", sizeof funcptr_test);
printf("sizeof3 = %d\n", sizeof(&funcptr_test));
printf("sizeof4 = %d\n", sizeof &funcptr_test);
a = 0;
func = num + a;
diff = func - num;
func(42);
(func + diff)(42);
(num + a)(43);
}
void lloptest(long long a, long long b)