QDict: Introduce qdict_get_qdict()
A helper to retrieve a QDict from a QDict. Signed-off-by: Luiz Capitulino <lcapitulino@redhat.com> Signed-off-by: Anthony Liguori <aliguori@us.ibm.com>
This commit is contained in:
parent
59eb1c85cd
commit
df10ce6aa9
13
qdict.c
13
qdict.c
@ -215,6 +215,19 @@ QList *qdict_get_qlist(const QDict *qdict, const char *key)
|
|||||||
return qobject_to_qlist(qdict_get_obj(qdict, key, QTYPE_QLIST));
|
return qobject_to_qlist(qdict_get_obj(qdict, key, QTYPE_QLIST));
|
||||||
}
|
}
|
||||||
|
|
||||||
|
/**
|
||||||
|
* qdict_get_qdict(): Get the QDict mapped by 'key'
|
||||||
|
*
|
||||||
|
* This function assumes that 'key' exists and it stores a
|
||||||
|
* QDict object.
|
||||||
|
*
|
||||||
|
* Return QDict mapped by 'key'.
|
||||||
|
*/
|
||||||
|
QDict *qdict_get_qdict(const QDict *qdict, const char *key)
|
||||||
|
{
|
||||||
|
return qobject_to_qdict(qdict_get_obj(qdict, key, QTYPE_QDICT));
|
||||||
|
}
|
||||||
|
|
||||||
/**
|
/**
|
||||||
* qdict_get_str(): Get a pointer to the stored string mapped
|
* qdict_get_str(): Get a pointer to the stored string mapped
|
||||||
* by 'key'
|
* by 'key'
|
||||||
|
1
qdict.h
1
qdict.h
@ -40,6 +40,7 @@ void qdict_iter(const QDict *qdict,
|
|||||||
int64_t qdict_get_int(const QDict *qdict, const char *key);
|
int64_t qdict_get_int(const QDict *qdict, const char *key);
|
||||||
int qdict_get_bool(const QDict *qdict, const char *key);
|
int qdict_get_bool(const QDict *qdict, const char *key);
|
||||||
QList *qdict_get_qlist(const QDict *qdict, const char *key);
|
QList *qdict_get_qlist(const QDict *qdict, const char *key);
|
||||||
|
QDict *qdict_get_qdict(const QDict *qdict, const char *key);
|
||||||
const char *qdict_get_str(const QDict *qdict, const char *key);
|
const char *qdict_get_str(const QDict *qdict, const char *key);
|
||||||
int64_t qdict_get_try_int(const QDict *qdict, const char *key,
|
int64_t qdict_get_try_int(const QDict *qdict, const char *key,
|
||||||
int64_t err_value);
|
int64_t err_value);
|
||||||
|
Loading…
Reference in New Issue
Block a user