SCSI divide capacity by s->cluster_size (Rik van Riel)
Paul Brook pointed out that the number of sectors reported by the SCSI read capacity commands needs to be divided by s->cluster_size, because bdrv_get_geometry reports the number of 512 byte sectors, while emulated CDROMs report 2048 byte sectors back to the guest. This has no consequences for emulated hard disks, which use a cluster size of 1. aliguori: fixed typo Signed-off-by: Rik van Riel <riel@redhat.com> Signed-off-by: Anthony Liguori <aliguori@us.ibm.com> git-svn-id: svn://svn.savannah.nongnu.org/qemu/trunk@6469 c046a42c-6fe2-441c-8c8c-71466251a162
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@ -734,6 +734,7 @@ static int32_t scsi_send_command(SCSIDevice *d, uint32_t tag,
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/* The normal LEN field for this command is zero. */
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memset(outbuf, 0, 8);
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bdrv_get_geometry(s->bdrv, &nb_sectors);
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nb_sectors /= s->cluster_size;
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/* Returned value is the address of the last sector. */
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if (nb_sectors) {
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nb_sectors--;
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@ -834,6 +835,7 @@ static int32_t scsi_send_command(SCSIDevice *d, uint32_t tag,
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DPRINTF("SAI READ CAPACITY(16)\n");
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memset(outbuf, 0, len);
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bdrv_get_geometry(s->bdrv, &nb_sectors);
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nb_sectors /= s->cluster_size;
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/* Returned value is the address of the last sector. */
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if (nb_sectors) {
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nb_sectors--;
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