i386: Emit correct error code for 64-bit IDT entry
When in 64-bit mode, IDT entiries are 16 bytes, so `intno * 16` is used for base/limit/offset calculations. However, even in 64-bit mode, the exception error code still uses bits [3,16) for the invlaid interrupt index. This means the error code should still be `intno * 8 + 2` even in 64-bit mode. Resolves: https://gitlab.com/qemu-project/qemu/-/issues/1382 Signed-off-by: Joe Richey <joerichey@google.com> Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
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@ -882,7 +882,7 @@ static void do_interrupt64(CPUX86State *env, int intno, int is_int,
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dt = &env->idt;
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if (intno * 16 + 15 > dt->limit) {
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raise_exception_err(env, EXCP0D_GPF, intno * 16 + 2);
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raise_exception_err(env, EXCP0D_GPF, intno * 8 + 2);
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}
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ptr = dt->base + intno * 16;
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e1 = cpu_ldl_kernel(env, ptr);
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@ -895,18 +895,18 @@ static void do_interrupt64(CPUX86State *env, int intno, int is_int,
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case 15: /* 386 trap gate */
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break;
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default:
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raise_exception_err(env, EXCP0D_GPF, intno * 16 + 2);
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raise_exception_err(env, EXCP0D_GPF, intno * 8 + 2);
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break;
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}
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dpl = (e2 >> DESC_DPL_SHIFT) & 3;
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cpl = env->hflags & HF_CPL_MASK;
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/* check privilege if software int */
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if (is_int && dpl < cpl) {
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raise_exception_err(env, EXCP0D_GPF, intno * 16 + 2);
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raise_exception_err(env, EXCP0D_GPF, intno * 8 + 2);
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}
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/* check valid bit */
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if (!(e2 & DESC_P_MASK)) {
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raise_exception_err(env, EXCP0B_NOSEG, intno * 16 + 2);
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raise_exception_err(env, EXCP0B_NOSEG, intno * 8 + 2);
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}
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selector = e1 >> 16;
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offset = ((target_ulong)e3 << 32) | (e2 & 0xffff0000) | (e1 & 0x0000ffff);
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