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qemu-io: Rework alloc command

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The alloc command in qemu-io is mostly useless currently. Instead of doing a
single call to bdrv_is_allocated, we must call bdrv_is_allocated in a loop
until we have found out for each requested sector if it is allocated or not
(bdrv_is_allocated returns a number of sectors that are known to be in the same
state as the first one, but it is not required to include all of them)

This changes the output format of the alloc command so that a change to the
expected output of qemu-iotests 019 is necessary once this is included.

Signed-off-by: Kevin Wolf <kwolf@redhat.com>
Signed-off-by: Anthony Liguori <aliguori@us.ibm.com>
This commit is contained in:
Kevin Wolf 2009-07-20 16:48:43 +02:00 committed by Anthony Liguori
parent d032044fb9
commit a7824a886e
1 changed files with 14 additions and 8 deletions
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20
qemu-io.c
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@ -1170,11 +1170,10 @@ static int
alloc_f(int argc, char **argv)
{
int64_t offset;
int nb_sectors;
int nb_sectors, remaining;
char s1[64];
int num;
int num, sum_alloc;
int ret;
const char *retstr;
offset = cvtnum(argv[1]);
if (offset & 0x1ff) {
@ -1188,16 +1187,23 @@ alloc_f(int argc, char **argv)
else
nb_sectors = 1;
remaining = nb_sectors;
sum_alloc = 0;
while (remaining) {
ret = bdrv_is_allocated(bs, offset >> 9, nb_sectors, &num);
remaining -= num;
if (ret) {
sum_alloc += num;
}
}
cvtstr(offset, s1, sizeof(s1));
retstr = ret ? "allocated" : "not allocated";
if (nb_sectors == 1)
printf("sector %s at offset %s\n", retstr, s1);
printf("sector allocated at offset %s\n", s1);
else
printf("%d/%d sectors %s at offset %s\n",
num, nb_sectors, retstr, s1);
printf("%d/%d sectors allocated at offset %s\n",
sum_alloc, nb_sectors, s1);
return 0;
}