migration/ram.c: fix typos in comments
Signed-off-by: Wei Yang <richardw.yang@linux.intel.com> Message-Id: <20190510233729.15554-1-richardw.yang@linux.intel.com> Reviewed-by: Dr. David Alan Gilbert <dgilbert@redhat.com> Signed-off-by: Dr. David Alan Gilbert <dgilbert@redhat.com>
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@ -917,7 +917,7 @@ struct {
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* - to make easier to know what to free at the end of migration
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*
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* This way we always know who is the owner of each "pages" struct,
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* and we don't need any loocking. It belongs to the migration thread
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* and we don't need any locking. It belongs to the migration thread
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* or to the channel thread. Switching is safe because the migration
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* thread is using the channel mutex when changing it, and the channel
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* have to had finish with its own, otherwise pending_job can't be
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@ -1630,7 +1630,7 @@ static int save_xbzrle_page(RAMState *rs, uint8_t **current_data,
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/**
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* migration_bitmap_find_dirty: find the next dirty page from start
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*
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* Returns the byte offset within memory region of the start of a dirty page
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* Returns the page offset within memory region of the start of a dirty page
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*
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* @rs: current RAM state
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* @rb: RAMBlock where to search for dirty pages
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@ -2144,7 +2144,7 @@ retry:
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* find_dirty_block: find the next dirty page and update any state
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* associated with the search process.
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*
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* Returns if a page is found
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* Returns true if a page is found
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*
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* @rs: current RAM state
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* @pss: data about the state of the current dirty page scan
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@ -2240,7 +2240,7 @@ static RAMBlock *unqueue_page(RAMState *rs, ram_addr_t *offset)
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*
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* Skips pages that are already sent (!dirty)
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*
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* Returns if a queued page is found
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* Returns true if a queued page is found
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*
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* @rs: current RAM state
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* @pss: data about the state of the current dirty page scan
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@ -3447,7 +3447,7 @@ static int ram_save_iterate(QEMUFile *f, void *opaque)
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/* we want to check in the 1st loop, just in case it was the 1st time
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and we had to sync the dirty bitmap.
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qemu_get_clock_ns() is a bit expensive, so we only check each some
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qemu_clock_get_ns() is a bit expensive, so we only check each some
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iterations
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*/
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if ((i & 63) == 0) {
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