block: Fix order in bdrv_replace_child()

Commit 8ee03995 refactored the code incorrectly and broke the release of
permissions on the old BDS. Instead of changing the permissions to the
new required values after removing the old BDS from the list of
children, it only re-obtains the permissions it already had.

Change the order of operations so that the old BDS is removed again
before calculating the new required permissions.

Signed-off-by: Kevin Wolf <kwolf@redhat.com>
Reviewed-by: Eric Blake <eblake@redhat.com>
Reviewed-by: Jeff Cody <jcody@redhat.com>
Reviewed-by: John Snow <jsnow@redhat.com>
This commit is contained in:
Kevin Wolf 2017-08-03 17:02:57 +02:00
parent e5e6268348
commit 8aecf1d1bd

View File

@ -1933,6 +1933,8 @@ static void bdrv_replace_child(BdrvChild *child, BlockDriverState *new_bs)
BlockDriverState *old_bs = child->bs;
uint64_t perm, shared_perm;
bdrv_replace_child_noperm(child, new_bs);
if (old_bs) {
/* Update permissions for old node. This is guaranteed to succeed
* because we're just taking a parent away, so we're loosening
@ -1942,8 +1944,6 @@ static void bdrv_replace_child(BdrvChild *child, BlockDriverState *new_bs)
bdrv_set_perm(old_bs, perm, shared_perm);
}
bdrv_replace_child_noperm(child, new_bs);
if (new_bs) {
bdrv_get_cumulative_perm(new_bs, &perm, &shared_perm);
bdrv_set_perm(new_bs, perm, shared_perm);