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softfloat: do not set denominator high bit for floatx80 remainder

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The floatx80 remainder implementation unnecessarily sets the high bit
of bSig explicitly.  By that point in the function, arguments that are
invalid, zero, infinity or NaN have already been handled and
subnormals have been through normalizeFloatx80Subnormal, so the high
bit will already be set.  Remove the unnecessary code.

Signed-off-by: Joseph Myers <joseph@codesourcery.com>
Reviewed-by: Richard Henderson <richard.henderson@linaro.org>
Message-Id: <alpine.DEB.2.21.2006081656220.23637@digraph.polyomino.org.uk>
Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
This commit is contained in:
Joseph Myers 2020-06-08 16:56:47 +00:00 committed by Paolo Bonzini
parent b662495dca
commit 566601f1f9
1 changed files with 0 additions and 1 deletions
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fpu/softfloat.c
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@ -5751,7 +5751,6 @@ floatx80 floatx80_modrem(floatx80 a, floatx80 b, bool mod,
if ( aSig0 == 0 ) return a;
normalizeFloatx80Subnormal( aSig0, &aExp, &aSig0 );
}
bSig |= UINT64_C(0x8000000000000000);
zSign = aSign;
expDiff = aExp - bExp;
aSig1 = 0;