x86_iommu/amd: remove V=1 check from amdvi_validate_dte()

Currently, the amdvi_validate_dte() assumes that a valid DTE will
always have V=1. This is not true. The V=1 means that bit[127:1] are
valid. A valid DTE can have IV=1 and V=0 (i.e address translation
disabled and interrupt remapping enabled)

Remove the V=1 check from amdvi_validate_dte(), make the caller
responsible to check for V or IV bits.

This also fixes a bug in existing code that when error is
detected during the translation we'll fail the translation
instead of assuming a passthrough mode.

Signed-off-by: Brijesh Singh <brijesh.singh@amd.com>
Reviewed-by: Peter Xu <peterx@redhat.com>
Cc: Peter Xu <peterx@redhat.com>
Cc: "Michael S. Tsirkin" <mst@redhat.com>
Cc: Paolo Bonzini <pbonzini@redhat.com>
Cc: Richard Henderson <rth@twiddle.net>
Cc: Eduardo Habkost <ehabkost@redhat.com>
Cc: Marcel Apfelbaum <marcel.apfelbaum@gmail.com>
Cc: Tom Lendacky <Thomas.Lendacky@amd.com>
Cc: Suravee Suthikulpanit <Suravee.Suthikulpanit@amd.com>
Reviewed-by: Michael S. Tsirkin <mst@redhat.com>
Signed-off-by: Michael S. Tsirkin <mst@redhat.com>
This commit is contained in:
Singh, Brijesh 2018-10-01 19:44:32 +00:00 committed by Michael S. Tsirkin
parent 35c2450191
commit 470506b582

View File

@ -807,7 +807,7 @@ static inline uint64_t amdvi_get_perms(uint64_t entry)
AMDVI_DEV_PERM_SHIFT;
}
/* a valid entry should have V = 1 and reserved bits honoured */
/* validate that reserved bits are honoured */
static bool amdvi_validate_dte(AMDVIState *s, uint16_t devid,
uint64_t *dte)
{
@ -820,7 +820,7 @@ static bool amdvi_validate_dte(AMDVIState *s, uint16_t devid,
return false;
}
return dte[0] & AMDVI_DEV_VALID;
return true;
}
/* get a device table entry given the devid */
@ -966,8 +966,12 @@ static void amdvi_do_translate(AMDVIAddressSpace *as, hwaddr addr,
return;
}
/* devices with V = 0 are not translated */
if (!amdvi_get_dte(s, devid, entry)) {
return;
}
/* devices with V = 0 are not translated */
if (!(entry[0] & AMDVI_DEV_VALID)) {
goto out;
}