x86_iommu/amd: remove V=1 check from amdvi_validate_dte()
Currently, the amdvi_validate_dte() assumes that a valid DTE will always have V=1. This is not true. The V=1 means that bit[127:1] are valid. A valid DTE can have IV=1 and V=0 (i.e address translation disabled and interrupt remapping enabled) Remove the V=1 check from amdvi_validate_dte(), make the caller responsible to check for V or IV bits. This also fixes a bug in existing code that when error is detected during the translation we'll fail the translation instead of assuming a passthrough mode. Signed-off-by: Brijesh Singh <brijesh.singh@amd.com> Reviewed-by: Peter Xu <peterx@redhat.com> Cc: Peter Xu <peterx@redhat.com> Cc: "Michael S. Tsirkin" <mst@redhat.com> Cc: Paolo Bonzini <pbonzini@redhat.com> Cc: Richard Henderson <rth@twiddle.net> Cc: Eduardo Habkost <ehabkost@redhat.com> Cc: Marcel Apfelbaum <marcel.apfelbaum@gmail.com> Cc: Tom Lendacky <Thomas.Lendacky@amd.com> Cc: Suravee Suthikulpanit <Suravee.Suthikulpanit@amd.com> Reviewed-by: Michael S. Tsirkin <mst@redhat.com> Signed-off-by: Michael S. Tsirkin <mst@redhat.com>
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@ -807,7 +807,7 @@ static inline uint64_t amdvi_get_perms(uint64_t entry)
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AMDVI_DEV_PERM_SHIFT;
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}
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/* a valid entry should have V = 1 and reserved bits honoured */
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/* validate that reserved bits are honoured */
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static bool amdvi_validate_dte(AMDVIState *s, uint16_t devid,
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uint64_t *dte)
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{
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@ -820,7 +820,7 @@ static bool amdvi_validate_dte(AMDVIState *s, uint16_t devid,
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return false;
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}
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return dte[0] & AMDVI_DEV_VALID;
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return true;
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}
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/* get a device table entry given the devid */
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@ -966,8 +966,12 @@ static void amdvi_do_translate(AMDVIAddressSpace *as, hwaddr addr,
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return;
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}
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/* devices with V = 0 are not translated */
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if (!amdvi_get_dte(s, devid, entry)) {
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return;
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}
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/* devices with V = 0 are not translated */
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if (!(entry[0] & AMDVI_DEV_VALID)) {
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goto out;
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}
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