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Makefile: use $(INSTALL_LIB) for modules not $(INSTALL_PROG)

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We have $(INSTALL_LIB) which is the same as $(INSTALL_PROG) but
uses correct permissions.  Loadable objects (modules) are like
shared libraries, not like programs.

Signed-off-by: Michael Tokarev <mjt@tls.msk.ru>
Cc: Fam Zheng <famz@redhat.com>
Cc: Paolo Bonzini <pbonzini@redhat.com>
Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
This commit is contained in:
Michael Tokarev 2014-05-08 15:06:03 +04:00 committed by Paolo Bonzini
parent 8f98aeb9c0
commit 264f8b4fdc
1 changed files with 1 additions and 1 deletions
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Makefile
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@ -381,7 +381,7 @@ ifneq ($(CONFIG_MODULES),)
$(INSTALL_DIR) "$(DESTDIR)$(qemu_moddir)"
for s in $(modules-m:.mo=$(DSOSUF)); do \
t="$(DESTDIR)$(qemu_moddir)/$$(echo $$s | tr / -)"; \
$(INSTALL_PROG) $$s "$$t"; \
$(INSTALL_LIB) $$s "$$t"; \
test -z "$(STRIP)" || $(STRIP) "$$t"; \
done
endif