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Use additional ORDER BY to cope with new sorting routines.

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This commit is contained in:
Thomas G. Lockhart 1997-09-24 17:55:38 +00:00
parent 16d65f5c25
commit d77a506307
2 changed files with 3 additions and 3 deletions
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4
src/test/regress/expected/point.out
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@ -179,14 +179,14 @@ thirty|point1 |point2
QUERY: SELECT '' AS fifteen, p1.f1 AS point1, p2.f1 AS point2, (p1.f1 <-> p2.f1) AS distance QUERY: SELECT '' AS fifteen, p1.f1 AS point1, p2.f1 AS point2, (p1.f1 <-> p2.f1) AS distance
FROM POINT_TBL p1, POINT_TBL p2 FROM POINT_TBL p1, POINT_TBL p2
WHERE (p1.f1 <-> p2.f1) > 3 and p1.f1 << p2.f1 WHERE (p1.f1 <-> p2.f1) > 3 and p1.f1 << p2.f1
ORDER BY distance; ORDER BY distance, point1 using <<, point2 using <<;
fifteen|point1 |point2 | distance fifteen|point1 |point2 | distance
-------+----------+----------+---------------- -------+----------+----------+----------------
|(-3,4) |(0,0) | 5 |(-3,4) |(0,0) | 5
|(-10,0) |(-3,4) |8.06225774829855 |(-10,0) |(-3,4) |8.06225774829855
|(-10,0) |(0,0) | 10 |(-10,0) |(0,0) | 10
|(-5,-12) |(0,0) | 13
|(-10,0) |(-5,-12) | 13 |(-10,0) |(-5,-12) | 13
|(-5,-12) |(0,0) | 13
|(0,0) |(10,10) | 14.142135623731 |(0,0) |(10,10) | 14.142135623731
|(-3,4) |(10,10) |14.3178210632764 |(-3,4) |(10,10) |14.3178210632764
|(-5,-12) |(-3,4) |16.1245154965971 |(-5,-12) |(-3,4) |16.1245154965971

2
src/test/regress/sql/point.sql
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@ -67,7 +67,7 @@ SELECT '' AS thirty, p1.f1 AS point1, p2.f1 AS point2
SELECT '' AS fifteen, p1.f1 AS point1, p2.f1 AS point2, (p1.f1 <-> p2.f1) AS distance SELECT '' AS fifteen, p1.f1 AS point1, p2.f1 AS point2, (p1.f1 <-> p2.f1) AS distance
FROM POINT_TBL p1, POINT_TBL p2 FROM POINT_TBL p1, POINT_TBL p2
WHERE (p1.f1 <-> p2.f1) > 3 and p1.f1 << p2.f1 WHERE (p1.f1 <-> p2.f1) > 3 and p1.f1 << p2.f1
ORDER BY distance; ORDER BY distance, point1 using <<, point2 using <<;
-- put distance result into output to allow sorting with GEQ optimizer - tgl 97/05/10 -- put distance result into output to allow sorting with GEQ optimizer - tgl 97/05/10
SELECT '' AS three, p1.f1 AS point1, p2.f1 AS point2, (p1.f1 <-> p2.f1) AS distance SELECT '' AS three, p1.f1 AS point1, p2.f1 AS point2, (p1.f1 <-> p2.f1) AS distance