Recognize that IN subqueries return already-unique results if they use
UNION/INTERSECT/EXCEPT (without ALL). This adds on to the previous optimization for subqueries using DISTINCT.
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@ -8,7 +8,7 @@
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*
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*
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* IDENTIFICATION
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* $PostgreSQL: pgsql/src/backend/optimizer/util/pathnode.c,v 1.99 2004/01/05 23:39:54 tgl Exp $
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* $PostgreSQL: pgsql/src/backend/optimizer/util/pathnode.c,v 1.100 2004/01/19 03:49:41 tgl Exp $
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*
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*-------------------------------------------------------------------------
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*/
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@ -33,6 +33,7 @@
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#include "utils/syscache.h"
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static bool is_distinct_query(Query *query);
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static bool hash_safe_tlist(List *tlist);
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@ -553,16 +554,14 @@ create_unique_path(Query *root, RelOptInfo *rel, Path *subpath)
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pathnode->subpath = subpath;
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/*
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* If the input is a subquery that uses DISTINCT, we don't need to do
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* anything; its output is already unique. (Are there any other cases
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* in which we can easily prove the input must be distinct?)
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* If the input is a subquery whose output must be unique already,
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* we don't need to do anything.
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*/
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if (rel->rtekind == RTE_SUBQUERY)
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{
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RangeTblEntry *rte = rt_fetch(rel->relid, root->rtable);
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Query *subquery = rte->subquery;
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if (has_distinct_clause(subquery))
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if (is_distinct_query(rte->subquery))
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{
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pathnode->umethod = UNIQUE_PATH_NOOP;
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pathnode->rows = rel->rows;
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@ -667,6 +666,36 @@ create_unique_path(Query *root, RelOptInfo *rel, Path *subpath)
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return pathnode;
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}
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/*
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* is_distinct_query - does query never return duplicate rows?
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*/
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static bool
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is_distinct_query(Query *query)
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{
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/* DISTINCT (but not DISTINCT ON) guarantees uniqueness */
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if (has_distinct_clause(query))
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return true;
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/* UNION, INTERSECT, EXCEPT guarantee uniqueness, except with ALL */
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if (query->setOperations)
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{
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SetOperationStmt *topop = (SetOperationStmt *) query->setOperations;
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Assert(IsA(topop, SetOperationStmt));
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Assert(topop->op != SETOP_NONE);
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if (!topop->all)
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return true;
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}
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/*
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* XXX Are there any other cases in which we can easily see the result
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* must be distinct?
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*/
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return false;
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}
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/*
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* hash_safe_tlist - can datatypes of given tlist be hashed?
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*
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