pg_upgrade: Avoid check target accidentally breaking make's --output-sync.
When $(MAKE) is present in a rule, make assumes that target is a submake, and it doesn't need to buffer its output. But in this case it's a shell script that needs buffered output. Avoid that heuristic, by referring to $(MAKE) via an indirection. Discussion: https://postgr.es/m/20190521004717.qsktdsugj3shagco@alap3.anarazel.de
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@ -35,8 +35,17 @@ clean distclean maintainer-clean:
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pg_upgrade_dump_globals.sql \
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pg_upgrade_dump_*.custom pg_upgrade_*.log
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# When $(MAKE) is present, make automatically infers that this is a
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# recursive make. which is not actually what we want here, as that
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# e.g. prevents output synchronization from working (as make thinks
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# that the subsidiary make knows how to deal with that itself, but
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# we're invoking a shell script that doesn't know). Referencing
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# $(MAKE) indirectly avoids that behaviour.
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# See https://www.gnu.org/software/make/manual/html_node/MAKE-Variable.html#MAKE-Variable
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NOTSUBMAKEMAKE=$(MAKE)
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check: test.sh all temp-install
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MAKE=$(MAKE) $(with_temp_install) bindir=$(abs_top_builddir)/tmp_install/$(bindir) EXTRA_REGRESS_OPTS="$(EXTRA_REGRESS_OPTS)" $(SHELL) $<
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MAKE=$(NOTSUBMAKEMAKE) $(with_temp_install) bindir=$(abs_top_builddir)/tmp_install/$(bindir) EXTRA_REGRESS_OPTS="$(EXTRA_REGRESS_OPTS)" $(SHELL)
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# installcheck is not supported because there's no meaningful way to test
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# pg_upgrade against a single already-running server
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