update stress test with more documentation
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@ -5,9 +5,14 @@ terms of the MIT license.
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-----------------------------------------------------------------------------*/
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/* This is a stress test for the allocator, using multiple threads and
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transferring objects between threads. This is not a typical workload
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but uses a random linear size distribution. Timing can also depend on
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(random) thread scheduling. Do not use this test as a benchmark!
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transferring objects between threads. It tries to reflect real-world workloads:
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- allocation size is distributed linearly in powers of two
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- with some fraction extra large (and some extra extra large)
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- the allocations are initialized and read again at free
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- pointers transfer between threads
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- threads are terminated and recreated with some objects surviving in between
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- uses deterministic "randomness", but execution can still depend on
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(random) thread scheduling. Do not use this test as a benchmark!
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*/
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#include <stdio.h>
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@ -22,13 +27,13 @@ terms of the MIT license.
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// argument defaults
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static int THREADS = 32; // more repeatable if THREADS <= #processors
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static int SCALE = 50; // scaling factor
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static int ITER = 10; // N full iterations re-creating all threads
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static int ITER = 10; // N full iterations destructing and re-creating all threads
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// static int THREADS = 8; // more repeatable if THREADS <= #processors
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// static int SCALE = 100; // scaling factor
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static bool allow_large_objects = true; // allow very large objects?
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static size_t use_one_size = 0; // use single object size of N uintptr_t?
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static size_t use_one_size = 0; // use single object size of `N * sizeof(uintptr_t)`?
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#ifdef USE_STD_MALLOC
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@ -185,7 +190,7 @@ int main(int argc, char** argv) {
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long n = (strtol(argv[3], &end, 10));
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if (n > 0) ITER = n;
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}
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printf("start with %d threads with a %d%% load-per-thread and %d iterations\n", THREADS, SCALE, ITER);
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printf("Using %d threads with a %d%% load-per-thread and %d iterations\n", THREADS, SCALE, ITER);
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//int res = mi_reserve_huge_os_pages(4,1);
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//printf("(reserve huge: %i\n)", res);
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@ -204,7 +209,7 @@ int main(int argc, char** argv) {
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}
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mi_collect(false);
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#ifndef NDEBUG
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if ((n + 1) % 10 == 0) { printf("- iterations: %3d\n", n + 1); }
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if ((n + 1) % 10 == 0) { printf("- iterations left: %3d\n", ITER - n + 1); }
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#endif
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}
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