Avoid compilation error when passing in heap to allocators
Before it would not work to create the mi_heap_stl_allocator types with passing in a "mi_heap_t*", since sizeof is used and it gives a compilation error. This change fixes that.
This commit is contained in:
parent
db52999d85
commit
068dc014ec
@ -487,6 +487,7 @@ template<class T1,class T2> bool operator!=(const mi_stl_allocator<T1>& , const
|
||||
#define MI_HAS_HEAP_STL_ALLOCATOR 1
|
||||
|
||||
#include <memory> // std::shared_ptr
|
||||
#include "mimalloc/types.h"
|
||||
|
||||
// Common base class for STL allocators in a specific heap
|
||||
template<class T, bool _mi_destroy> struct _mi_heap_stl_allocator_common : public _mi_stl_allocator_common<T> {
|
||||
|
Loading…
x
Reference in New Issue
Block a user