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lua_call cannot be a macro, because it would push the function 

over the parameters
This commit is contained in:
Roberto Ierusalimschy 1994-11-09 16:10:11 -02:00
parent fc0de64c2c
commit d0780fa16d
1 changed files with 2 additions and 3 deletions
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5
lua.h
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@ -2,7 +2,7 @@
** LUA - Linguagem para Usuarios de Aplicacao
** Grupo de Tecnologia em Computacao Grafica
** TeCGraf - PUC-Rio
** $Id: lua.h,v 3.4 1994/11/07 18:27:39 roberto Exp roberto $
** $Id: lua.h,v 3.5 1994/11/08 19:56:39 roberto Exp roberto $
*/
@ -35,6 +35,7 @@ void lua_error (char *s);
int lua_dofile (char *filename);
int lua_dostring (char *string);
int lua_callfunction (lua_Object function);
int lua_call (char *funcname);
lua_Object lua_getparam (int number);
#define lua_getresult lua_getparam
@ -69,8 +70,6 @@ void lua_unlock (int ref);
#define lua_register(n,f) (lua_pushcfunction(f), lua_storeglobal(n))
#define lua_call(f) lua_callfunction(lua_getglobal(f))
#define lua_getindexed(o,n) (lua_pushobject(o), lua_pushnumber(n), lua_getsubscript())
#define lua_getfield(o,f) (lua_pushobject(o), lua_pushstring(f), lua_getsubscript())