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Dereferencing a function shouldn't do anything

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This is an oddity in the C spec, but you can apply the unary `*`
operator to a function as many times as you want. `*x` and `x`
means exactly the same, given that `x` is a function.
This commit is contained in:
Rui Ueyama 2020-04-23 17:18:49 +09:00
parent 603de502fd
commit e0b5da3b39
2 changed files with 13 additions and 2 deletions
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13
parse.c
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@ -1947,8 +1947,17 @@ static Node *unary(Token **rest, Token *tok) {
if (equal(tok, "&"))
return new_unary(ND_ADDR, cast(rest, tok->next), tok);
if (equal(tok, "*"))
return new_unary(ND_DEREF, cast(rest, tok->next), tok);
if (equal(tok, "*")) {
// [https://www.sigbus.info/n1570#6.5.3.2p4] This is an oddity
// in the C spec, but dereferencing a function shouldn't do
// anything. If foo is a function, `*foo`, `**foo` or `*****foo`
// are all equivalent to just `foo`.
Node *node = cast(rest, tok->next);
add_type(node);
if (node->ty->kind == TY_FUNC)
return node;
return new_unary(ND_DEREF, node, tok);
}
if (equal(tok, "!"))
return new_unary(ND_NOT, cast(rest, tok->next), tok);

2
test/function.c
View File

@ -363,6 +363,8 @@ int main() {
ASSERT(15, struct_test38().a[14]);
ASSERT(20, struct_test38().a[19]);
ASSERT(5, (***add2)(2,3));
printf("OK\n");
return 0;
}