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<div id="projectbrief">Set of algorithms implemented in C.</div>
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<p>Implementation of <a href="https://en.wikipedia.org/wiki/Collatz_conjecture" target="_blank">Collatz' conjecture</a>
<a href="#details">More...</a></p>
<div class="textblock"><code>#include &lt;stdio.h&gt;</code><br />
<code>#include &lt;stdlib.h&gt;</code><br />
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Include dependency graph for collatz.c:</div>
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Functions</h2></td></tr>
<tr class="memitem:a0ddf1224851353fc92bfbff6f499fa97"><td class="memItemLeft" align="right" valign="top">int&#160;</td><td class="memItemRight" valign="bottom"><a class="el" href="../../dc/d80/collatz_8c.html#a0ddf1224851353fc92bfbff6f499fa97">main</a> (int argc, char *argv[])</td></tr>
<tr class="memdesc:a0ddf1224851353fc92bfbff6f499fa97"><td class="mdescLeft">&#160;</td><td class="mdescRight">Main function. <a href="../../dc/d80/collatz_8c.html#a0ddf1224851353fc92bfbff6f499fa97">More...</a><br /></td></tr>
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<a name="details" id="details"></a><h2 class="groupheader">Detailed Description</h2>
<div class="textblock"><p >Implementation of <a href="https://en.wikipedia.org/wiki/Collatz_conjecture" target="_blank">Collatz' conjecture</a> </p>
<p >Collatz conjecture: a series for a number \(n\) in which if \(n\) even then the next number is \(\frac{n}{2}\) ,but if n is odd then the next number is \(3n+1\). This series continues till \(n\) reaches 1 </p>
</div><h2 class="groupheader">Function Documentation</h2>
<a id="a0ddf1224851353fc92bfbff6f499fa97" name="a0ddf1224851353fc92bfbff6f499fa97"></a>
<h2 class="memtitle"><span class="permalink"><a href="#a0ddf1224851353fc92bfbff6f499fa97">&#9670;&#160;</a></span>main()</h2>
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<td class="memname">int main </td>
<td>(</td>
<td class="paramtype">int&#160;</td>
<td class="paramname"><em>argc</em>, </td>
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<td class="paramkey"></td>
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<td class="paramtype">char *&#160;</td>
<td class="paramname"><em>argv</em>[]&#160;</td>
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<p>Main function. </p>
<div class="fragment"><div class="line"><span class="lineno"> 17</span>{</div>
<div class="line"><span class="lineno"> 18</span> <span class="keywordtype">unsigned</span> <span class="keywordtype">long</span> <span class="keywordtype">long</span> n, curr_no, num_steps = 0;</div>
<div class="line"><span class="lineno"> 19</span> <span class="keywordflow">if</span> (argc == 2)</div>
<div class="line"><span class="lineno"> 20</span> n = strtoull(argv[1], NULL, 10);</div>
<div class="line"><span class="lineno"> 21</span> <span class="keywordflow">else</span></div>
<div class="line"><span class="lineno"> 22</span> {</div>
<div class="line"><span class="lineno"> 23</span> printf(<span class="stringliteral">&quot;Enter starting number: &quot;</span>);</div>
<div class="line"><span class="lineno"> 24</span> scanf(<span class="stringliteral">&quot;%lu&quot;</span>, &amp;n); <span class="comment">// input number</span></div>
<div class="line"><span class="lineno"> 25</span> }</div>
<div class="line"><span class="lineno"> 26</span> </div>
<div class="line"><span class="lineno"> 27</span> curr_no = n; <span class="comment">// curr_no stores input number n</span></div>
<div class="line"><span class="lineno"> 28</span> <span class="keywordflow">while</span> (curr_no != 1) <span class="comment">// loop till series reaches 1</span></div>
<div class="line"><span class="lineno"> 29</span> {</div>
<div class="line"><span class="lineno"> 30</span> num_steps++;</div>
<div class="line"><span class="lineno"> 31</span> printf(<span class="stringliteral">&quot;%llu-&gt;&quot;</span>, curr_no);</div>
<div class="line"><span class="lineno"> 32</span> <span class="keywordflow">if</span> (curr_no % 2 == 0) <span class="comment">// condition for even number</span></div>
<div class="line"><span class="lineno"> 33</span> curr_no = curr_no / 2;</div>
<div class="line"><span class="lineno"> 34</span> <span class="keywordflow">else</span></div>
<div class="line"><span class="lineno"> 35</span> curr_no = (curr_no * 3) + 1; <span class="comment">// condition for odd number</span></div>
<div class="line"><span class="lineno"> 36</span> }</div>
<div class="line"><span class="lineno"> 37</span> printf(<span class="stringliteral">&quot;1\nNumber of steps: %llu\n&quot;</span>, num_steps);</div>
<div class="line"><span class="lineno"> 38</span> <span class="keywordflow">return</span> 0;</div>
<div class="line"><span class="lineno"> 39</span>}</div>
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