diff --git a/leetcode/src/69.c b/leetcode/src/69.c
new file mode 100644
index 00000000..63c0d025
--- /dev/null
+++ b/leetcode/src/69.c
@@ -0,0 +1,23 @@
+//using the binary search method is one of the efficient ones for this problem statement.
+int mySqrt(int x){
+int start=0;
+        int end=x;
+        long long int ans=0;
+        while(start <= end){
+               long long int mid=(start+end)/2;
+               long long int val=mid*mid;
+               if( val == x){
+                   return mid;
+                }
+//if mid is less than the square root of the number(x) store the value of mid in ans.
+               if( val < x){
+                       ans = mid;
+                       start = mid+1;
+               }
+//if mid is greater than the square root of the number(x) then ssign the value mid-1 to end.               
+               if( val > x){
+                       end = mid-1;
+               }
+        }
+   return ans;
+}