feat: add `dynamic_programming` to CMake lists (#1266)

* feat: add `dynamic_programming` to CMake lists

* updating DIRECTORY.md

* chore: fix minor doc. issues and indentation

---------

Co-authored-by: github-actions[bot] <github-actions@users.noreply.github.com>
This commit is contained in:
David Leal 2023-06-13 10:45:46 -06:00 committed by GitHub
parent 2e8374e5c1
commit b6b01a3605
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3 changed files with 57 additions and 26 deletions

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@ -65,6 +65,7 @@ add_subdirectory(process_scheduling_algorithms)
add_subdirectory(numerical_methods)
add_subdirectory(math)
add_subdirectory(cipher)
add_subdirectory(dynamic_programming)
## Configure Doxygen documentation system
cmake_policy(SET CMP0054 NEW)

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@ -0,0 +1,18 @@
# If necessary, use the RELATIVE flag, otherwise each source file may be listed
# with full pathname. The RELATIVE flag makes it easier to extract an executable's name
# automatically.
file( GLOB APP_SOURCES RELATIVE ${CMAKE_CURRENT_SOURCE_DIR} *.c )
foreach( testsourcefile ${APP_SOURCES} )
string( REPLACE ".c" "" testname ${testsourcefile} ) # File type. Example: `.c`
add_executable( ${testname} ${testsourcefile} )
if(OpenMP_C_FOUND)
target_link_libraries(${testname} OpenMP::OpenMP_C)
endif()
if(MATH_LIBRARY)
target_link_libraries(${testname} ${MATH_LIBRARY})
endif()
install(TARGETS ${testname} DESTINATION "bin/dynamic_programming") # Folder name. Do NOT include `<>`
endforeach( testsourcefile ${APP_SOURCES} )

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@ -1,12 +1,15 @@
/**
* @file
* @brief [Longest Common Subsequence](https://en.wikipedia.org/wiki/Longest_common_subsequence_problem) algorithm
* @brief [Longest Common
* Subsequence](https://en.wikipedia.org/wiki/Longest_common_subsequence_problem)
* algorithm
* @details
* From Wikipedia: The longest common subsequence (LCS) problem is the problem
* of finding the longest subsequence common to all sequences in a set of sequences
* (often just two sequences).
* of finding the longest subsequence common to all sequences in a set of
* sequences (often just two sequences).
* @author [Kurtz](https://github.com/itskurtz)
*/
#include <stdio.h> /* for io operations */
#include <stdlib.h> /* for memory management & exit */
#include <string.h> /* for string manipulation & ooperations */
@ -15,13 +18,13 @@
enum {LEFT, UP, DIAG};
/**
* @breif Computes LCS between s1 and s2 using a dynamic-programming approach
* @param1 s1 first null-terminated string
* @param2 s2 second null-terminated string
* @param3 l1 length of s1
* @param4 l2 length of s2
* @param5 L matrix of size l1 x l2
* @param6 B matrix of size l1 x l2
* @brief Computes LCS between s1 and s2 using a dynamic-programming approach
* @param s1 first null-terminated string
* @param s2 second null-terminated string
* @param l1 length of s1
* @param l2 length of s2
* @param L matrix of size l1 x l2
* @param B matrix of size l1 x l2
* @returns void
*/
void lcslen(const char *s1, const char *s2, int l1, int l2, int **L, int **B) {
@ -31,8 +34,8 @@ void lcslen(const char *s1, const char *s2, int l1, int l2, int **L, int **B) {
/* loop over the simbols in my sequences
save the directions according to the LCS */
for (i = 1; i <= l1; ++i)
for (j = 1; j <= l2; ++j)
for (i = 1; i <= l1; ++i) {
for (j = 1; j <= l2; ++j) {
if (s1[i-1] == s2[j-1]) {
L[i][j] = 1 + L[i-1][j-1];
B[i][j] = DIAG;
@ -46,14 +49,16 @@ void lcslen(const char *s1, const char *s2, int l1, int l2, int **L, int **B) {
B[i][j] = UP;
}
}
}
}
/**
* @breif Builds the LCS according to B using a traceback approach
* @param1 s1 first null-terminated string
* @param2 l1 length of s1
* @param3 l2 length of s2
* @param4 L matrix of size l1 x l2
* @param5 B matrix of size l1 x l2
* @brief Builds the LCS according to B using a traceback approach
* @param s1 first null-terminated string
* @param l1 length of s1
* @param l2 length of s2
* @param L matrix of size l1 x l2
* @param B matrix of size l1 x l2
* @returns lcs longest common subsequence
*/
char *lcsbuild(const char *s1, int l1, int l2, int **L, int **B) {
@ -77,12 +82,17 @@ char *lcsbuild(const char *s1, int l1, int l2, int **L, int **B) {
j = j - 1;
}
else if (B[i][j] == LEFT)
{
j = j - 1;
}
else
{
i = i - 1;
}
}
return lcs;
}
/**
* @brief Self-test implementations
* @returns void
@ -134,7 +144,9 @@ static void test() {
free(lcs);
for (j = 0; j <= l1; j++)
{
free(L[j]), free(B[j]);
}
free(L);
free(B);