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feat: leetcode Construct Binary Search Tree from Preorder Traversal solution (1008) (#1021)
Co-authored-by: David Leal <halfpacho@gmail.com>
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| 938 | [Range Sum of BST](https://leetcode.com/problems/range-sum-of-bst/) | [C](./src/938.c) | Easy |
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| 965 | [Univalued Binary Tree](https://leetcode.com/problems/univalued-binary-tree/) | [C](./src/965.c) | Easy |
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| 977 | [Squares of a Sorted Array](https://leetcode.com/problems/squares-of-a-sorted-array/) | [C](./src/977.c) | Easy |
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| 1008 | [Construct Binary Search Tree from Preorder Traversal](https://leetcode.com/problems/construct-binary-search-tree-from-preorder-traversal/description/) | [C](./src/1008.c) | Medium |
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| 1019 | [Next Greater Node In Linked List](https://leetcode.com/problems/next-greater-node-in-linked-list/) | [C](./src/1019.c) | Medium |
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| 1089 | [Duplicate Zeros](https://leetcode.com/problems/duplicate-zeros/) | [C](./src/1089.c) | Easy |
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| 1184 | [Distance Between Bus Stops](https://leetcode.com/problems/distance-between-bus-stops/) | [C](./src/1184.c) | Easy |
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| 1189 | [Maximum Number of Balloons](https://leetcode.com/problems/maximum-number-of-balloons/) | [C](./src/1189.c) | Easy |
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| 1207 | [Unique Number of Occurrences](https://leetcode.com/problems/unique-number-of-occurrences/) | [C](./src/1207.c) | Easy |
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| 2130 | [Maximum Twin Sum of a Linked List](https://leetcode.com/problems/maximum-twin-sum-of-a-linked-list/) | [C](./src/2130.c) | Medium |
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| 2130 | [Maximum Twin Sum of a Linked List](https://leetcode.com/problems/maximum-twin-sum-of-a-linked-list/) | [C](./src/2130.c) | Medium |
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leetcode/src/1008.c
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leetcode/src/1008.c
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/**
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* Definition for a binary tree node.
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* struct TreeNode {
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* int val;
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* struct TreeNode *left;
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* struct TreeNode *right;
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* };
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*/
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struct TreeNode* bstFromPreorder(int* preorder, int preorderSize)
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{
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struct TreeNode* new;
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int left_ptr;
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new = malloc(sizeof(struct TreeNode));
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new->val = preorder[0];
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if (preorderSize == 1)
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{
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new->right = NULL;
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new->left = NULL;
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return new;
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}
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left_ptr = 1;
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while ((left_ptr < preorderSize) && (preorder[left_ptr] < preorder[0]))
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left_ptr++;
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if (left_ptr == 1)
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new->left = NULL;
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else
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new->left = bstFromPreorder(preorder + 1, left_ptr - 1);
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if (left_ptr < preorderSize)
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new->right =
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bstFromPreorder(preorder + left_ptr, preorderSize - left_ptr);
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else
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new->right = NULL;
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return new;
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}
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