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added semi-implicit euler method
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numerical_methods/ode_semi_implicit_euler.c
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182
numerical_methods/ode_semi_implicit_euler.c
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/**
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* \file
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* \authors [Krishna Vedala](https://github.com/kvedala)
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* \brief Solve a multivariable first order [ordinary differential equation
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* (ODEs)](https://en.wikipedia.org/wiki/Ordinary_differential_equation) using
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* [semi implicit Euler
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* method](https://en.wikipedia.org/wiki/Semi-implicit_Euler_method)
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*
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* \description
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* The ODE being solved is:
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* \f{eqnarray*}{
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* \dot{u} &=& v\\
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* \dot{v} &=& -\omega^2 u\\
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* \omega &=& 1\\
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* [x_0, u_0, v_0] &=& [0,1,0]\qquad\ldots\text{(initial values)}
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* \f}
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* The exact solution for the above problem is:
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* \f{eqnarray*}{
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* u(x) &=& \cos(x)\\
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* v(x) &=& -\sin(x)\\
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* \f}
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* The computation results are stored to a text file `semi_implicit_euler.csv`
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* and the exact soltuion results in `exact.csv` for comparison. <img
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* src="https://raw.githubusercontent.com/kvedala/C/docs/images/numerical_methods/ode_semi_implicit_euler.svg"
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* alt="Implementation solution"/>
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* \see ode_forward_euler.c, ode_midpoint_euler.c
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*/
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#include <math.h>
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#include <stdio.h>
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#include <stdlib.h>
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#include <time.h>
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#define order 2 /**< number of dependent variables in ::problem */
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/**
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* @brief Problem statement for a system with first-order differential
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* equations. Updates the system differential variables.
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* \note This function can be updated to and ode of any order.
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*
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* @param[in] x independent variable(s)
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* @param[in,out] y dependent variable(s)
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* @param[in,out] dy first-derivative of dependent variable(s)
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*/
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void problem(const double *x, double *y, double *dy)
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{
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const double omega = 1.F; // some const for the problem
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dy[0] = y[1]; // x dot
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dy[1] = -omega * omega * y[0]; // y dot
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}
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/**
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* @brief Exact solution of the problem. Used for solution comparison.
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*
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* @param[in] x independent variable
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* @param[in,out] y dependent variable
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*/
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void exact_solution(const double *x, double *y)
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{
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y[0] = cos(x[0]);
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y[1] = -sin(x[0]);
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}
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/**
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* @brief Compute next step approximation using the midpoint-Euler
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* method.
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* @f[y_{n+1} = y_n + dx\, f\left(x_n+\frac{1}{2}dx,
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* y_n + \frac{1}{2}dx\,f\left(x_n,y_n\right)\right)@f]
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* @param[in] dx step size
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* @param[in,out] x take @f$x_n@f$ and compute @f$x_{n+1}@f$
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* @param[in,out] y take @f$y_n@f$ and compute @f$y_{n+1}@f$
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* @param[in,out] dy compute @f$y_n+\frac{1}{2}dx\,f\left(x_n,y_n\right)@f$
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*/
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void semi_implicit_euler_step(double dx, double *x, double *y, double *dy)
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{
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problem(x, y, dy);
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double tmp_x = (*x) + 0.5 * dx;
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double tmp_y[order];
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int o;
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for (o = 0; o < order; o++)
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tmp_y[o] = y[o] + 0.5 * dx * dy[o];
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problem(&tmp_x, tmp_y, dy);
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for (o = 0; o < order; o++)
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y[o] += dx * dy[o];
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}
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/**
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* @brief Compute approximation using the midpoint-Euler
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* method in the given limits.
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* @param[in] dx step size
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* @param[in] x0 initial value of independent variable
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* @param[in] x_max final value of independent variable
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* @param[in,out] y take \f$y_n\f$ and compute \f$y_{n+1}\f$
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* @param[in] save_to_file flag to save results to a CSV file (1) or not (0)
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* @returns time taken for computation in seconds
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*/
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double semi_implicit_euler(double dx, double x0, double x_max, double *y,
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char save_to_file)
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{
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double dy[order];
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FILE *fp = NULL;
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if (save_to_file)
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{
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fp = fopen("semi_implicit_euler.csv", "w+");
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if (fp == NULL)
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{
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perror("Error! ");
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return -1;
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}
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}
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/* start integration */
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clock_t t1 = clock();
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double x = x0;
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do // iterate for each step of independent variable
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{
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if (save_to_file && fp)
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fprintf(fp, "%.4g,%.4g,%.4g\n", x, y[0], y[1]); // write to file
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semi_implicit_euler_step(dx, &x, y, dy); // perform integration
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x += dx; // update step
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} while (x <= x_max); // till upper limit of independent variable
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/* end of integration */
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clock_t t2 = clock();
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if (save_to_file && fp)
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fclose(fp);
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return (double)(t2 - t1) / CLOCKS_PER_SEC;
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}
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/**
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Main Function
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*/
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int main(int argc, char *argv[])
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{
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double X0 = 0.f; /* initial value of x0 */
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double X_MAX = 10.F; /* upper limit of integration */
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double Y0[] = {1.f, 0.f}; /* initial value Y = y(x = x_0) */
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double step_size;
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if (argc == 1)
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{
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printf("\nEnter the step size: ");
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scanf("%lg", &step_size);
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}
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else
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// use commandline argument as independent variable step size
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step_size = atof(argv[1]);
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// get approximate solution
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double total_time = semi_implicit_euler(step_size, X0, X_MAX, Y0, 1);
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printf("\tTime = %.6g ms\n", total_time);
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/* compute exact solution for comparion */
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FILE *fp = fopen("exact.csv", "w+");
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if (fp == NULL)
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{
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perror("Error! ");
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return -1;
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}
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double x = X0;
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double *y = &(Y0[0]);
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printf("Finding exact solution\n");
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clock_t t1 = clock();
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do
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{
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fprintf(fp, "%.4g,%.4g,%.4g\n", x, y[0], y[1]); // write to file
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exact_solution(&x, y);
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x += step_size;
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} while (x <= X_MAX);
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clock_t t2 = clock();
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total_time = (t2 - t1) / CLOCKS_PER_SEC;
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printf("\tTime = %.6g ms\n", total_time);
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fclose(fp);
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return 0;
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}
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