Euler prob# 10 using sieve of Eratosthenes

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Krishna Vedala 2020-03-29 22:21:49 -04:00
parent 266383a700
commit 747a50d3ca
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#include <stdio.h>
#include <math.h>
#include <stdlib.h>
int main(int argc, char* argv[])
{
long n = 100;
long long sum = 0;
char *sieve = NULL;
if (argc == 2) /* if command line argument is provided */
n = atol(argv[1]); /* use that as the upper limit */
/* allocate memory for the sieve */
sieve = calloc(n, sizeof(*sieve));
if(!sieve)
{
perror("Unable to allocate memory!");
return -1;
}
/* build sieve of Eratosthenes
In the array,
* if i^th cell is '1', then 'i' is composite
* if i^th cell is '0', then 'i' is prime
*/
for (long i = 2; i < sqrtl(n)+1; i++)
{
/* if i^th element is prime, mark all its multiples
as composites */
if (!sieve[i])
{
for (long j = i * i; j < n + 1; j += i)
{
sieve[j] = 1;
}
sum += i;
}
}
for (long i = sqrtl(n)+1; i < n; i++)
if (!sieve[i])
sum += i;
free(sieve);
printf("%ld: %lld\n", n, sum);
return 0;
}