feat: add matrix chain order (#1198)

* feat: add Matrix Chain Order

* updating DIRECTORY.md

* Update dynamic_programming/matrix_chain_order.c

Co-authored-by: David Leal <halfpacho@gmail.com>

* Update dynamic_programming/matrix_chain_order.c

Co-authored-by: David Leal <halfpacho@gmail.com>

* Update dynamic_programming/matrix_chain_order.c

Co-authored-by: David Leal <halfpacho@gmail.com>

* Update matrix_chain_order.c

* chore: apply suggestions from code review

* chore: apply suggestions from code review

* updating DIRECTORY.md

* Update dynamic_programming/matrix_chain_order.c

Co-authored-by: Taj <tjgurwara99@users.noreply.github.com>

* updating DIRECTORY.md

* updating DIRECTORY.md

---------

Co-authored-by: github-actions[bot] <github-actions@users.noreply.github.com>
Co-authored-by: David Leal <halfpacho@gmail.com>
Co-authored-by: Taj <tjgurwara99@users.noreply.github.com>
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## Dynamic Programming ## Dynamic Programming
* [Lcs](https://github.com/TheAlgorithms/C/blob/HEAD/dynamic_programming/lcs.c) * [Lcs](https://github.com/TheAlgorithms/C/blob/HEAD/dynamic_programming/lcs.c)
* [Matrix Chain Order](https://github.com/TheAlgorithms/C/blob/HEAD/dynamic_programming/matrix_chain_order.c)
## Exercism ## Exercism
* Acronym * Acronym
@ -180,6 +181,7 @@
* [11](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/11.c) * [11](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/11.c)
* [110](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/110.c) * [110](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/110.c)
* [112](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/112.c) * [112](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/112.c)
* [1137](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/1137.c)
* [1147](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/1147.c) * [1147](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/1147.c)
* [118](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/118.c) * [118](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/118.c)
* [1184](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/1184.c) * [1184](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/1184.c)
@ -304,6 +306,7 @@
* [977](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/977.c) * [977](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/977.c)
* [98](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/98.c) * [98](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/98.c)
* [985](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/985.c) * [985](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/985.c)
* [997](https://github.com/TheAlgorithms/C/blob/HEAD/leetcode/src/997.c)
## Machine Learning ## Machine Learning
* [Adaline Learning](https://github.com/TheAlgorithms/C/blob/HEAD/machine_learning/adaline_learning.c) * [Adaline Learning](https://github.com/TheAlgorithms/C/blob/HEAD/machine_learning/adaline_learning.c)

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/**
* @file
* @brief [Matrix Chain Order](https://en.wikipedia.org/wiki/Matrix_chain_multiplication)
* @details
* From Wikipedia: Matrix chain multiplication (or the matrix chain ordering problem)
* is an optimization problem concerning the most efficient way to multiply a given sequence of matrices.
* The problem is not actually to perform the multiplications,
* but merely to decide the sequence of the matrix multiplications involved.
* @author [CascadingCascade](https://github.com/CascadingCascade)
*/
#include <assert.h> /// for assert
#include <stdio.h> /// for IO operations
#include <limits.h> /// for INT_MAX macro
#include <stdlib.h> /// for malloc() and free()
/**
* @brief Finds the optimal sequence using the classic O(n^3) algorithm.
* @param l length of cost array
* @param p costs of each matrix
* @param s location to store results
* @returns number of operations
*/
int matrixChainOrder(int l,const int *p, int *s) {
// mat stores the cost for a chain that starts at i and ends on j (inclusive on both ends)
int mat[l][l];
for (int i = 0; i < l; ++i) {
mat[i][i] = 0;
}
// cl denotes the difference between start / end indices, cl + 1 would be chain length.
for (int cl = 1; cl < l; ++cl) {
for (int i = 0; i < l - cl; ++i) {
int j = i + cl;
mat[i][j] = INT_MAX;
for (int div = i; div < j; ++div) {
int q = mat[i][div] + mat[div + 1][j] + p[i] * p[div] * p[j];
if (q < mat[i][j]) {
mat[i][j] = q;
s[i * l + j] = div;
}
}
}
}
return mat[0][l - 1];
}
/**
* @brief Recursively prints the solution
* @param l dimension of the solutions array
* @param s solutions
* @param i starting index
* @param j ending index
* @returns void
*/
void printSolution(int l,int *s,int i,int j) {
if(i == j) {
printf("A%d",i);
return
}
putchar('(');
printSolution(l,s,i,s[i * l + j]);
printSolution(l,s,s[i * l + j] + 1,j);
putchar(')');
}
/**
* @brief Self-test implementations
* @returns void
*/
static void test() {
int sizes[] = {35,15,5,10,20,25};
int len = 6;
int *sol = malloc(len * len * sizeof(int));
int r = matrixChainOrder(len,sizes,sol);
assert(r == 18625);
printf("Result : %d\n",r);
printf("Optimal ordering : ");
printSolution(len,sol,0,5);
free(sol);
printf("\n");
}
/**
* @brief Main function
* @returns 0
*/
int main() {
test(); // run self-test implementations
return 0;
}