Update linear_search.c

A shorter and simple understandable code...
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Sankalp Sharma 2024-11-18 10:55:29 +05:30 committed by GitHub
parent e5dad3fa8d
commit 1c042cbca4
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@ -1,36 +1,20 @@
#include <stdio.h>
#include <stdlib.h>
int linearsearch(int *arr, int size, int val)
{
int i;
for (i = 0; i < size; i++)
{
if (arr[i] == val)
return 1;
}
return 0;
int search(int array[], int n, int x) {
// Going through array sequencially
for (int i = 0; i < n; i++)
if (array[i] == x)
return i;
return -1;
}
int main()
{
int n, i, v;
printf("Enter the size of the array:\n");
scanf("%d", &n); // Taking input for the size of Array
int main() {
int array[] = {2, 4, 0, 1, 9};
int x = 1;
int n = sizeof(array) / sizeof(array[0]);
int *a = (int *)malloc(n * sizeof(int));
printf("Enter the contents for an array of size %d:\n", n);
for (i = 0; i < n; i++)
scanf("%d", &a[i]); // accepts the values of array elements until the
// loop terminates//
int result = search(array, n, x);
printf("Enter the value to be searched:\n");
scanf("%d", &v); // Taking input the value to be searched
if (linearsearch(a, n, v))
printf("Value %d is in the array.\n", v);
else
printf("Value %d is not in the array.\n", v);
free(a);
return 0;
(result == -1) ? printf("Element not found") : printf("Element found at index: %d", result);
}