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Commented code to explain algorithms in 190 and 191
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@ -32,6 +32,7 @@ LeetCode
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|169|[Majority Element](https://leetcode.com/problems/majority-element/) | [C](./src/169.c)|Easy|
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|173|[Binary Search Tree Iterator](https://leetcode.com/problems/binary-search-tree-iterator/) | [C](./src/173.c)|Medium|
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|190|[Reverse Bits](https://leetcode.com/problems/reverse-bits/) | [C](./src/190.c)|Easy|
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|191|[Number of 1 Bits](https://leetcode.com/problems/number-of-1-bits/) | [C](./src/191.c)|Easy|
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|203|[Remove Linked List Elements](https://leetcode.com/problems/remove-linked-list-elements/) | [C](./src/203.c)|Easy|
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|206|[Reverse Linked List](https://leetcode.com/problems/reverse-linked-list/) | [C](./src/206.c)|Easy|
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|215|[Kth Largest Element in an Array](https://leetcode.com/problems/kth-largest-element-in-an-array/) | [C](./src/215.c)|Medium|
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@ -47,7 +48,6 @@ LeetCode
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|389|[Find the Difference](https://leetcode.com/problems/find-the-difference/) | [C](./src/389.c)|Easy|
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|404|[Sum of Left Leaves](https://leetcode.com/problems/sum-of-left-leaves/) | [C](./src/404.c)|Easy|
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|442|[Find All Duplicates in an Array](https://leetcode.com/problems/find-all-duplicates-in-an-array/) | [C](./src/442.c)|Medium|
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|461|[Hamming Distance](https://leetcode.com/problems/hamming-distance/) | [C](./src/461.c)|Easy|
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|509|[Fibonacci Number](https://leetcode.com/problems/fibonacci-number/) | [C](./src/509.c)|Easy|
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|520|[Detect Capital](https://leetcode.com/problems/detect-capital/) | [C](./src/520.c)|Easy|
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|561|[Array Partition I](https://leetcode.com/problems/array-partition-i/) | [C](./src/561.c)|Easy|
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@ -1,10 +1,13 @@
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uint32_t reverseBits(uint32_t n) {
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uint TotalBits = 32;
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uint32_t reverse_int = 0;
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uint32_t reverse_int = 0; //stored in memory as 32 bits, each bit valued 0
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uint i;
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for(i = 0; i < TotalBits; i++) {
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if((n & (UINT32_C(1) << i)))
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reverse_int = reverse_int | (UINT32_C(1) << (TotalBits - 1 - i));
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if((n & (UINT32_C(1) << i))) //if the bit on the ith position of 32 bit input is 1, then proceed
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//Further note the use of UINT32_C to convert 1 to unsigned 32 bit int, since just 1 is treated as int which cannot be shifted left more than 30 times
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reverse_int = reverse_int | (UINT32_C(1) << (TotalBits - 1 - i)); //Convert the ith bit from the end in reverse_int from 0 to 1, if ith bit from beginning in n is 1
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//This is achieved by using bitwise OR on reverse_int (where ith bit from end is currently 0) and
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//1 shifted left 31 - i bits (to ith bit from the end)
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}
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return reverse_int;
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}
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10
leetcode/src/191.c
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10
leetcode/src/191.c
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@ -0,0 +1,10 @@
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int hammingWeight(uint32_t n) {
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int TotalBits = 32;
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int i, weight = 0;
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for(i = 0; i < TotalBits; i++) {
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if(n & (UINT32_C(1) << i)) //if the bit on the ith position of 32 bit input is 1, then proceed
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//Further note the use of UINT32_C to convert 1 to unsigned 32 bit int, as just 1 is treated as int which cannot be shifted left more than 30 times
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weight += 1;
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}
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return weight;
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}
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@ -1,10 +0,0 @@
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int hammingDistance(int x, int y){
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int difference = x ^ y;
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int TotalBits = sizeof(difference)*8;
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int i, distance = 0;
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for(i = 0; i < TotalBits; i++) {
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if(difference & (UINT32_C(1) << i))
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distance += 1;
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}
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return distance;
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}
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