7515c32c1f
gcc could apparently assume that the register assigned to the one in the clobber list would keep its value (as can be observed when disassembling add_debugger_command_etc()). Using a dummy output register works around the problem and also avoids the unnecessary initialization of the register. Comments explaining the mystery welcome. git-svn-id: file:///srv/svn/repos/haiku/haiku/trunk@30909 a95241bf-73f2-0310-859d-f6bbb57e9c96
68 lines
1.4 KiB
C
68 lines
1.4 KiB
C
/*
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* Copyright 2005, Axel Dörfler, axeld@pinc-software.de. All rights reserved.
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* Distributed under the terms of the MIT License.
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*/
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#ifndef _KERNEL_ARCH_x86_INT_H
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#define _KERNEL_ARCH_x86_INT_H
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#define ARCH_INTERRUPT_BASE 0x20
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#define NUM_IO_VECTORS (256 - ARCH_INTERRUPT_BASE)
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static inline void
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arch_int_enable_interrupts_inline(void)
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{
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asm volatile("sti");
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}
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static inline int
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arch_int_disable_interrupts_inline(void)
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{
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int flags;
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asm volatile("pushfl;\n"
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"popl %0;\n"
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"cli" : "=g" (flags));
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return flags & 0x200 ? 1 : 0;
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}
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static inline void
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arch_int_restore_interrupts_inline(int oldstate)
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{
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int flags = oldstate ? 0x200 : 0;
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asm volatile("pushfl;\n"
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"popl %0;\n"
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"andl $0xfffffdff,%0;\n"
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"orl %1,%0;\n"
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"pushl %0;\n"
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"popfl\n"
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: "=&r"(flags) : "r"(flags));
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}
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static inline bool
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arch_int_are_interrupts_enabled_inline(void)
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{
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int flags;
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asm volatile("pushfl;\n"
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"popl %0;\n" : "=g" (flags));
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return flags & 0x200 ? 1 : 0;
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}
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// map the functions to the inline versions
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#define arch_int_enable_interrupts() arch_int_enable_interrupts_inline()
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#define arch_int_disable_interrupts() arch_int_disable_interrupts_inline()
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#define arch_int_restore_interrupts(status) \
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arch_int_restore_interrupts_inline(status)
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#define arch_int_are_interrupts_enabled() \
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arch_int_are_interrupts_enabled_inline()
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#endif /* _KERNEL_ARCH_x86_INT_H */
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