115 lines
2.2 KiB
ArmAsm
115 lines
2.2 KiB
ArmAsm
/* $NetBSD: strlen.S,v 1.2 1998/04/03 22:59:30 matthias Exp $ */
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/*
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* Written by Randy Hyde, 1993
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* Public domain.
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*/
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#include <machine/asm.h>
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#if defined(LIBC_SCCS)
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RCSID("$NetBSD: strlen.S,v 1.2 1998/04/03 22:59:30 matthias Exp $")
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#endif
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/*
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* size_t
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* strlen (char *s)
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* compute the length of the string s.
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*/
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KENTRY(strlen, 4)
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enter [r3,r4],0
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movd B_ARG0,r0
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/*
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* First begin by seeing if we can doubleword align the
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* pointer. The following code aligns the pointer in r0.
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*/
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movqd 3,r3
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andd r0,r3
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0: casew 1f(pc)[r3:w]
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1: .word 5f-0b
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.word 2f-0b
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.word 3f-0b
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.word 4f-0b
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.align 2,0xa2
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2: cmpqb 0,0(r0) ; beq 7f
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cmpqb 0,1(r0) ; beq 8f
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cmpqb 0,2(r0) ; beq 9f
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addqd 3,r0
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br 5f
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.align 2,0xa2
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3: cmpqb 0,0(r0) ; beq 7f
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cmpqb 0,1(r0) ; beq 8f
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addqd 2,r0
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br 5f
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.align 2,0xa2
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4: cmpqb 0,0(r0) ; beq 7f
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addqd 1,r0
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/*
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* Okay, when we get down here r0 points at a double word
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* algined source block of bytes.
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* This guy processes four bytes at a time and checks for the
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* zero terminating byte amongst the bytes in the double word.
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* This algorithm is de to Dave Rand.
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*
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* Sneaky test for zero amongst four bytes:
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*
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* xxyyzztt
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* -01010101
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* ---------
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* aabbccdd
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* bic xxyyzztt
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* ---------
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* eeffgghh ee=0x80 if xx=0, ff=0x80 if yy=0, etc.
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*
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* This whole result will be zero if there
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* was no zero byte, it will be non-zero if
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* there is a zero byte present.
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*/
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5: movd 0x01010101,r2 /* Magic number to use */
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movd 0x80808080,r3 /* Another magic number. */
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addqd -4,r0
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.align 2,0xa2
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0: movd 4(r0),r1 /* Get next double word. */
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addqd 4,r0 /* Advance pointer. */
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movd r1,r4 /* Save for storage later. */
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subd r2,r1 /* Gets borrow if byte = 0. */
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bicd r4,r1 /* Clear original bits. */
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andd r3,r1 /* See if borrow occurred. */
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cmpqd 0,r1
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beq 0b /* See if this DWORD contained a 0. */
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/*
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* At this point, r0 points at a double word which
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* contains a zero byte. Count the bytes up to the
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* zero.
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*/
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1: cmpqb 0,0(r0) ; beq 7f
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cmpqb 0,1(r0) ; beq 8f
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cmpqb 0,2(r0) ; beq 9f
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addqd 3,r0 /* Must be in fourth byte. */
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7: subd B_ARG0,r0
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exit [r3,r4]
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ret ARGS
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8: addqd 1,r0
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subd B_ARG0,r0
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exit [r3,r4]
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ret ARGS
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9: addqd 2,r0
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subd B_ARG0,r0
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exit [r3,r4]
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ret ARGS
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