NetBSD/gnu/lib/regex-0.12/test/syntax.skel

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/* Print which syntax bits are set. */
#include <sys/types.h>
#include <stdio.h>
#include "regex.h"
/* It's coincidental that these two are currently the same. */
#define LONGEST_BIT_NAME "RE_UNMATCHED_RIGHT_PAREN_ORD"
#define LAST_BIT RE_UNMATCHED_RIGHT_PAREN_ORD
/* Sum of above, when printed. Assigned in main. */
static unsigned longest;
static void
test_bit (syntax, bit, name)
reg_syntax_t syntax;
unsigned bit;
char *name;
{
char padding[100], test_str[100];
int padding_count;
sprintf (test_str, "%s (%d=0x%x)", name, bit, bit);
padding_count = longest - strlen (test_str);
padding[padding_count] = 0;
while (padding_count--)
{
padding[padding_count] = ' ';
}
printf ("%s%s (%d=0x%x): %c\n",
name, padding, bit, bit, syntax & bit ? 'y' : 'n');
}
/* Macro to abbreviate the constant arguments. */
#define TEST_BIT(bit) test_bit (syntax, bit, #bit)
int
main (argc, argv)
int argc;
char *argv[];
{
reg_syntax_t syntax;
char syntax_str[1000], test_str[100];
switch (argc)
{
case 1:
printf ("Syntax? ");
scanf ("%s", syntax_str);
break;
case 2:
strcpy (syntax_str, argv[1]);
break;
default:
fprintf (stderr, "Usage: syntax [syntax].\n");
exit (1);
}
sscanf (syntax_str, "%i", &syntax);
/* Figure out the longest name, so we can align the output nicely. */
sprintf (test_str, "%s (%d=0x%x)", LONGEST_BIT_NAME, LAST_BIT, LAST_BIT);
longest = strlen (test_str);
/* [[[replace with bit tests]]] */
return 0;
}