116 lines
2.9 KiB
C
116 lines
2.9 KiB
C
/* $NetBSD: ex_abbrev.c,v 1.1.1.2 2008/05/18 14:31:09 aymeric Exp $ */
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/*-
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* Copyright (c) 1992, 1993, 1994
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* The Regents of the University of California. All rights reserved.
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* Copyright (c) 1992, 1993, 1994, 1995, 1996
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* Keith Bostic. All rights reserved.
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*
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* See the LICENSE file for redistribution information.
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*/
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#include "config.h"
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#ifndef lint
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static const char sccsid[] = "Id: ex_abbrev.c,v 10.10 2001/12/16 18:18:54 skimo Exp (Berkeley) Date: 2001/12/16 18:18:54";
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#endif /* not lint */
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#include <sys/types.h>
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#include <sys/queue.h>
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#include <sys/time.h>
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#include <bitstring.h>
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#include <ctype.h>
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#include <limits.h>
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#include <stdio.h>
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#include <stdlib.h>
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#include <string.h>
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#include "../common/common.h"
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#include "../vi/vi.h"
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/*
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* ex_abbr -- :abbreviate [key replacement]
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* Create an abbreviation or display abbreviations.
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*
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* PUBLIC: int ex_abbr __P((SCR *, EXCMD *));
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*/
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int
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ex_abbr(SCR *sp, EXCMD *cmdp)
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{
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CHAR_T *p;
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size_t len;
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switch (cmdp->argc) {
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case 0:
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if (seq_dump(sp, SEQ_ABBREV, 0) == 0)
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msgq(sp, M_INFO, "105|No abbreviations to display");
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return (0);
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case 2:
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break;
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default:
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abort();
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}
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/*
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* Check for illegal characters.
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*
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* !!!
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* Another fun one, historically. See vi/v_ntext.c:txt_abbrev() for
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* details. The bottom line is that all abbreviations have to end
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* with a "word" character, because it's the transition from word to
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* non-word characters that triggers the test for an abbreviation. In
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* addition, because of the way the test is done, there can't be any
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* transitions from word to non-word character (or vice-versa) other
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* than between the next-to-last and last characters of the string,
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* and there can't be any <blank> characters. Warn the user.
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*/
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if (!inword(cmdp->argv[0]->bp[cmdp->argv[0]->len - 1])) {
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msgq(sp, M_ERR,
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"106|Abbreviations must end with a \"word\" character");
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return (1);
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}
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for (p = cmdp->argv[0]->bp; *p != '\0'; ++p)
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if (ISBLANK(p[0])) {
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msgq(sp, M_ERR,
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"107|Abbreviations may not contain tabs or spaces");
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return (1);
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}
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if (cmdp->argv[0]->len > 2)
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for (p = cmdp->argv[0]->bp,
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len = cmdp->argv[0]->len - 2; len; --len, ++p)
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if (inword(p[0]) != inword(p[1])) {
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msgq(sp, M_ERR,
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"108|Abbreviations may not mix word/non-word characters, except at the end");
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return (1);
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}
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if (seq_set(sp, NULL, 0, cmdp->argv[0]->bp, cmdp->argv[0]->len,
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cmdp->argv[1]->bp, cmdp->argv[1]->len, SEQ_ABBREV, SEQ_USERDEF))
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return (1);
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F_SET(sp->gp, G_ABBREV);
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return (0);
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}
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/*
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* ex_unabbr -- :unabbreviate key
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* Delete an abbreviation.
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*
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* PUBLIC: int ex_unabbr __P((SCR *, EXCMD *));
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*/
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int
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ex_unabbr(SCR *sp, EXCMD *cmdp)
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{
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ARGS *ap;
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ap = cmdp->argv[0];
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if (!F_ISSET(sp->gp, G_ABBREV) ||
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seq_delete(sp, ap->bp, ap->len, SEQ_ABBREV)) {
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msgq_wstr(sp, M_ERR, ap->bp,
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"109|\"%s\" is not an abbreviation");
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return (1);
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}
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return (0);
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}
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