code reading, rather than any actual real use case failing.
With this script
f()
{
echo hello $1
}
exec 3>&1
echo $(
for i in a b c
do
echo @$i
f >&3
done >/tmp/foo
)
echo foo= $(cat /tmp/foo)
what should be output is
hello
hello
hello
foo= @a @b @c
but since the (my) 48875 fix the other day, we've been getting
hello
@b
hello
@c
hello
foo= @a
This fixes that. I think (hope) this is the last of these fixes...
3b5786dccc