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On sh3 __udivsi3 is gcc "millicode" with special calling convention 

(less registers clobbered than usual).  Each DSO that needs it gets
its own hidden copy from libgcc.a.  Do not compile udivsi3.c for sh3
here since this C version doesn't conform to what gcc expects and
overrides the libgcc.a version.

This makes binaries compiled with gcc4.8 work.  The issue was not
exposed with gcc4.5 since it uses different division strategy by
default.
This commit is contained in:
uwe 2014-03-19 20:30:53 +00:00
parent 5c1b7f4542
commit 66df54162c
1 changed files with 9 additions and 2 deletions
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11
lib/libc/compiler_rt/Makefile.inc
View File

@ -1,4 +1,4 @@
# $NetBSD: Makefile.inc,v 1.16 2014/03/02 03:04:52 matt Exp $
# $NetBSD: Makefile.inc,v 1.17 2014/03/19 20:30:53 uwe Exp $
COMPILER_RT_SRCDIR= ${NETBSDSRCDIR}/sys/external/bsd/compiler_rt/dist
@ -127,11 +127,18 @@ GENERIC_SRCS+= \
ucmpti2.c \
udivmodsi4.c \
udivmodti4.c \
udivsi3.c \
udivti3.c \
umodsi3.c \
umodti3.c
.if ${MACHINE_CPU} != "sh3"
# On sh3 __udivsi3 is gcc "millicode" with special calling convention
# (less registers clobbered than usual). Each DSO that needs it gets
# its own hidden copy from libgcc.a.
GENERIC_SRCS+= \
udivsi3.c
.endif
GENERIC_SRCS+= \
absvdi2.c \
addvdi3.c \