Fix typos found by Giorgos Keramid and Steve Kargl on freebsd-arch mailing

list.
This commit is contained in:
rpaulo 2005-08-02 14:20:49 +00:00
parent 969266b7d7
commit 270bc85b33
4 changed files with 12 additions and 12 deletions

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@ -6,14 +6,14 @@
#include <machine/asm.h>
#if defined(LIBC_SCCS)
RCSID("$NetBSD: memchr.S,v 1.3 2004/07/19 20:04:41 drochner Exp $")
RCSID("$NetBSD: memchr.S,v 1.4 2005/08/02 14:20:49 rpaulo Exp $")
#endif
ENTRY(memchr)
movzbq %sil,%rcx
/*
* Align to word boundry
* Align to word boundary.
* Consider unrolling loop?
*/
testq %rdx,%rdx /* nbytes == 0? */

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@ -6,7 +6,7 @@
#include <machine/asm.h>
#if defined(LIBC_SCCS)
RCSID("$NetBSD: strcmp.S,v 1.3 2004/07/19 20:04:41 drochner Exp $")
RCSID("$NetBSD: strcmp.S,v 1.4 2005/08/02 14:20:49 rpaulo Exp $")
#endif
ENTRY(strcmp)
@ -28,7 +28,7 @@ ENTRY(strcmp)
jmp .Ldone
/*
* Check whether s2 is aligned to a word boundry. If it is, we
* Check whether s2 is aligned to a word boundary. If it is, we
* can compare by words. Otherwise we have to compare by bytes.
*/
.Ls1aligned:

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@ -6,7 +6,7 @@
#include <machine/asm.h>
#if defined(LIBC_SCCS)
RCSID("$NetBSD: strlen.S,v 1.3 2004/07/19 20:04:41 drochner Exp $")
RCSID("$NetBSD: strlen.S,v 1.4 2005/08/02 14:20:49 rpaulo Exp $")
#endif
ENTRY(strlen)
@ -38,10 +38,10 @@ ENTRY(strlen)
* original word is zero.
*
* It also has the useful property that bytes in the result word
* that coorespond to non-zero bytes in the original word have
* the value 0x00, while bytes cooresponding to zero bytes have
* that correspond to non-zero bytes in the original word have
* the value 0x00, while bytes corresponding to zero bytes have
* the value 0x80. This allows calculation of the first (and
* last) occurance of a zero byte within the word (useful for C's
* last) occurrence of a zero byte within the word (useful for C's
* str* primitives) by counting the number of leading (or
* trailing) zeros and dividing the result by 8. On machines
* without (or with slow) clz() / ctz() instructions, testing
@ -59,10 +59,10 @@ ENTRY(strlen)
* original word is zero.
*
* On little endian machines, the first byte in the result word
* that cooresponds to a zero byte in the original byte is 0x80,
* that corresponds to a zero byte in the original byte is 0x80,
* so clz() can be used as above. On big endian machines, and
* little endian machines without (or with a slow) clz() insn,
* testing each byte in the original for zero is necessary
* testing each byte in the original for zero is necessary.
*
* This typically takes 3 instructions (4 on machines without
* "and with complement") not including those needed to load

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@ -6,7 +6,7 @@
#include <machine/asm.h>
#if defined(LIBC_SCCS)
RCSID("$NetBSD: swab.S,v 1.2 2003/07/26 19:24:40 salo Exp $")
RCSID("$NetBSD: swab.S,v 1.3 2005/08/02 14:20:49 rpaulo Exp $")
#endif
#define LOAD_SWAP_STORE_WORD \
@ -20,7 +20,7 @@ ENTRY(swab)
shrq $1,%rdx
testq $7,%rdx # copy first group of 1 to 7 words
jz L2 # while swaping alternate bytes.
jz L2 # while swapping alternate bytes.
L1: lodsw
rorw $8,%ax
stosw