indent: remove code for parsing declarations without semicolon
The statement from the comment that declarations do not need semicolons is wrong. A possible input that matched this rule is 'void f(void) { int a }'.
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@ -1,4 +1,4 @@
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/* $NetBSD: indent.c,v 1.254 2023/05/12 10:53:33 rillig Exp $ */
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/* $NetBSD: indent.c,v 1.255 2023/05/12 15:36:02 rillig Exp $ */
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/*-
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* SPDX-License-Identifier: BSD-4-Clause
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@ -43,7 +43,7 @@ static char sccsid[] = "@(#)indent.c 5.17 (Berkeley) 6/7/93";
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#include <sys/cdefs.h>
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#if defined(__NetBSD__)
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__RCSID("$NetBSD: indent.c,v 1.254 2023/05/12 10:53:33 rillig Exp $");
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__RCSID("$NetBSD: indent.c,v 1.255 2023/05/12 15:36:02 rillig Exp $");
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#elif defined(__FreeBSD__)
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__FBSDID("$FreeBSD: head/usr.bin/indent/indent.c 340138 2018-11-04 19:24:49Z oshogbo $");
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#endif
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@ -732,11 +732,6 @@ process_lbrace(void)
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static void
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process_rbrace(void)
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{
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if (ps.s_sym[ps.tos] == psym_decl && !ps.block_init) {
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/* semicolons can be omitted in declarations */
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parse(psym_semicolon);
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}
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if (ps.nparen > 0) { /* check for unclosed if, for, else. */
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diag(1, "Unbalanced parentheses");
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ps.nparen = 0;
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